An organisation is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets.The first and last addresses in subnet 1024 respectively are
Subnetting computer nw
Anmol_Binani
#2
Given the block as 130.56.0.0/16
now to create 1024 subnets, we need to select 10 bits from the Host_ID part, so now from :
130.56._ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _
if we select 10 bits then,
First subnet address will be 130.56.00000000.00 000000 --> (130.56.0.0)
Second subnet address will be 130.56.00000000.01 000000 --> (130.56.0.64)
Third subnet address will be 130.56.00000000.10 000000 --> (130.56.0.128)
so on … till the
Last subnet address will be 130.56.11111111.11 000000 --> (130.56.255.192)
So first and last address of the 1024 subnet are (130.56.255.192) and (130.56.255.255) respectively.
Mohit52
#3
please explain
So first and last address of the 1024 subnet are (130.56.255.192) and (130.56.255.255) respectively.
Anmol_Binani
#4
Since Last subnet address is 130.56.11111111.11 000000 --> (130.56.255.192)
so now the Host_Id of this subnet has 6 bits and we can have Host_Id filled as:
000000 --> 0 --------> First Host address 130.56.255.192 (130.56.11111111.11 000000)
000001 --> 1
000010 --> 2
so on till…
111111 --> 63 --------> Last Host Address 130.56.255.255 (130.56.11111111.11 111111)
I hope you get it now.
thanks