Let P(E) denote the probability of the occurrence of event E.

If P(A) = 0.5 and P(B) = 1, then the values of P(A/B) and P(B/A) respectively are

A)0.5, 0.25

B)0.25, 0.5

C)0.5, 1

D)1,0.5

Let P(E) denote the probability of the occurrence of event E.

If P(A) = 0.5 and P(B) = 1, then the values of P(A/B) and P(B/A) respectively are

A)0.5, 0.25

B)0.25, 0.5

C)0.5, 1

D)1,0.5

C. 0.5,1. Since both the events will occur the probability is P(A). i.e. P(A intersection B) = P(A).

Since the P(B)=1 it means it is a sure event.

- Now probability of intersection of both events A and B, i.e., P(A∩B)=P(A)
- P(A|B) = P(A∩B)/P(B) = P(A)/P(B) = 0.5/1 = 0.5
- P(B|A) = P(A∩B)/P(A) = P(A)/P(A) = 0.5/0.5 = 1

So the answer is option ‘c’.