Find the Maximum n such that the probability of getting no head in the tossing a fair coin n times is greater than 0.1

# Find Probability

**Nirbhay**#2

let p= probability of getting head =1/2

q=probability of getting tail= 1-p = 1/2

given that P(X=0) >0.1

i.e, ^{n}C_{0}p^{0}q^{n} > 0.1

i.e, q^{n}>0.1

replace q with 1/2,

=> (1/2)^{n} >0.1

=> 2^{n}<10

=>n<4

therefore n will be always less than 4.