A 2km long broadcast LAN has 10^7 bps bandwidth and uses CSMA/CD.The signal travels along the wire at 2x10^8 m/s.What is the minimum packet size that can be used on this network?(in bytes)


As we know

Transmission Time = 2(Length of packet/Bandwith)

According to question ,equation will be 2(2000/2×108) …equation 1

Now, we have Length of packet = equation 1 * 107
= 25 bytes

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Remember min packet size = 2BandwidthTime of propagation.
So the result is 25Bytes


Yes the answer is 25 bytes and the explaination is also correct