Ethernet....CSMA/CD


#1

A 2km long broadcast LAN has 10^7 bps bandwidth and uses CSMA/CD.The signal travels along the wire at 2x10^8 m/s.What is the minimum packet size that can be used on this network?(in bytes)


#2

As we know

Transmission Time = 2(Length of packet/Bandwith)

According to question ,equation will be 2(2000/2×108) …equation 1

Now, we have Length of packet = equation 1 * 107
= 25 bytes

Follow me for Gate 2019 at.

https://unacademy.com/lesson/overview-of-course-computer-architecture-and-organization/JR0MER13


#3

Remember min packet size = 2BandwidthTime of propagation.
So the result is 25Bytes


#4

Yes the answer is 25 bytes and the explaination is also correct