# De-Morgan law the value?

#1

De-Morgan law the value of bar(aVb) is given by

1. a(bar)Vb(bar)
2. a(bar)Vb
3. a(bar)b(bar)
4. ab(bar)

#2

The option is not there!! Using de Morgan’s law answer wille be a(bar)^b(bar). Here ^ represents AND operation.

#3

By demorgans law, it clearly states that the product of compliments is equal to compliments of sum i.e(a^b)bar=bar(A)ORbar(B).

SO by using the above law we can say that answer to your question is a(bar)^b(bar) where ^ represents AND operation.