Assume scenario where he size of CW of TCP connection is 40 KB when time out occurs ,MSS= 2KB ,Propagation delay = 200 msec , the time taken by TCP connection to get back 40KB CW is …msec
solution : one way P.D= 200 msec
new threshold =1/2* (40KB)=20 KB
15* 400=6000 msec
right?or missed something
I think it should be 14*400 instead of 15*400. because after 14 RTT your window size will be 40KB.
threshold is 20KB then SS till 16 then after 16 it should be 18 ,20,22,24,24,26,28,30,32,34,36,38,40 right?
Nopes after 16 it would be 20 then 22 24 so on.
why … 20 …
After 16 you can jump to 20 because if Th had not been applied then next size would have been 32.
Ananlogy: If you are allowed to drive the car at a speed of 80 kmps on an empty road, you can easily drive at a speed less than 80.
I hope you got it.