for two funtions

f(n)= n^3 if 0<=n<10,000

=n^2, otherwise

g(n)= n if 0<=n<100

=n^2+5n, otherwise

the complexity is same, how?

# Comparing complexities

**TEJASWI_D**#2

Because time complexity is being calculated for higher values so for f(n) we will take the time complexity which is greater than 10,000 ie n^2. Similarly for g(n) also we take otherwise part or greater than 100. It means for g(n) also the TC is n^2