Aptitude Questions


#1
  1. Find the units digit in (264)^102+(264)^103 ??

#2

May be it ZERO. As it will become (264)^102(265).


#3

The answer is zero as 264 raised to power even is 4 and odd is 6,so 4+6=10, 0 as units digit


#4

Given digits 2, 2, 3, 3, 3, 4, 4, 4, 4 how many distinct 4 digit numbers greater than 3000 can be formed?


#5

The answer is 0.
unit digit when 264 raised to even power is 6 and for odd power its 4.
so 6+4 =10. unit digit is 0.


#6

Answer is zero
We can solve this questions using cyclicity method
Cyclicity of 4 is 2.
4= 4,6,4
So by solving with this method the answer will 0


#7

The unit place will have number 4.

Since (264)^102 + (264)^103 = (264)^205
That is base is same, so powers get added.
Now considering unit number of base and power i.e 4^5 = 1024.
So results get 4 at unit place.


#8

Are u novice mr Shantanu


#9

by the solving this …i can say the answer will be zero.

unit digit.264 raised to even power is 6
ofcourse for odd power is 4.


#10

As u can see after taking 264^102 common ,the expression will be (264^102)*265 .
264^102 will be an even number n when u multiply an even number with 5 it’s unit digit will be zero always,
So yeah answer is a big “ZERO”


#11

haha,:slight_smile: You should have ended with
a BIG ZERO.
And a BIG ZERO IS STILL A ZERO.
SO ZERO.


#12

Hahaha yup right sir :smile::smile::smile:


#13

The answer is 0 when i solved it.


#14

it may be zero(0) or 4.