- Find the units digit in (264)^102+(264)^103 ??

# Aptitude Questions

**geetam**#3

The answer is zero as 264 raised to power even is 4 and odd is 6,so 4+6=10, 0 as units digit

Given digits 2, 2, 3, 3, 3, 4, 4, 4, 4 how many distinct 4 digit numbers greater than 3000 can be formed?

**shweta**#5

The answer is 0.

unit digit when 264 raised to even power is 6 and for odd power its 4.

so 6+4 =10. unit digit is 0.

**Empreet**#6

Answer is zero

We can solve this questions using cyclicity method

Cyclicity of 4 is 2.

4= 4,6,4

So by solving with this method the answer will 0

**Kr_Shantanu**#7

The unit place will have number 4.

Since (264)^102 + (264)^103 = (264)^205

That is base is same, so powers get added.

Now considering unit number of base and power i.e 4^5 = 1024.

So results get 4 at unit place.

**sam665**#9

by the solving this …i can say the answer will be zero.

unit digit.264 raised to even power is 6

ofcourse for odd power is 4.

**kishan_nagar**#10

As u can see after taking 264^102 common ,the expression will be (264^102)*265 .

264^102 will be an even number n when u multiply an even number with 5 it’s unit digit will be zero always,

So yeah answer is a big “ZERO”

**tarunprakashiit**#11

haha, You should have ended with

a BIG ZERO.

And a BIG ZERO IS STILL A ZERO.

SO ZERO.